if x/x^1.5=8x^-1 and x greater than 0 find x
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Answer:
given,
x/x^1.5 =8x^-1 (x is greater than 0)
LHS, x^1-1.5= x^0.5
RHS, 8x^-1= 8/x
so, x^0.5=8/x ( transfer x to LHS side)
x^0.5+1=8
x^1.5=8(transfer ^ 1.5 to LHS side)
x= 1.5√8
therefore, x= 4
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