Question

if x/x^1.5=8x^-1 and x>0,then x=​

Answer 1

Step-by-step explanation:

$\frac{x}{ {x}^{( \frac{15}{10}) } } = 8 {x}^{ - 1} \\ x. {x}^{ - \frac{3}{2} } = {2}^{3} . \frac{1}{x} \\ {x}^{(1 - \frac{3}{2} + 1) } = {2}^{3} \\ {x}^{ \frac{4- 3}{2} } = {2}^{3} \\ {x}^{ \frac{1}{2} } = {2}^{3} \\ x = {2}^{6} \\ x = 64$

Therefore x = 64 .

Answer 2

Answer:

x/x¹°⁵ = 8x ⁻¹

x⁽⁻¹°⁵⁾ = 8/x

x⁻⁰°⁵ = 8/x

x⁻¹/² = 8/x

x = 8√x

On Squaring Both Sides ,

x² = (8√x)

x² = 64x

x²/x = 64

x = 64

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