Question

If x + x/1 = 5 then find x^+x^/1 jaldi btao 20 points kamao​

Answer 1

Answer:

23

Step-by-step explanation:

I think there is an error in question

it hould be like

x+1/x = 5 then find x²+1/x².

So i am answering this question.

See, x+1/x =5

Now we can write

$(a+b)^2 = a^2 + b^2 + 2ab$

Now, put a = x and b = 1/x

∴ $(x+1/x)^2 = x^2 + (1/x)^2 + 2(x)(1/x)$

= $(x+1/x)^2 = x^2 + 1/x^2 + 2$         {as x*1/x = 1 and $(1/x)^2 = 1^2/x^2= 1/x^2$}

= $5^2 = x^2 + 1/x^2 + 2$        {as x+1/x =5}

= $25 = x^2 + 1/x^2 + 2$

= $x^2 + 1/x^2 = 25 - 2$

= $x^2 + 1/x^2 = 23$

Here, we got our answer.

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