Question

if X+x^3+k is exactly divisible by x-2 than find k​

Answer 1

Answer:

If x^3+6x^2+4x+k is exactly divisible by x+2 then we can say- (-2)^3+6(-2)^2+4(-2)+k=0

or, -8+24-8+k=0

or,k+8=0

or, k=(-8)