if [X + [X]] less than or equal 2 then X belongs to
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(−∞,−2)∪(0,4)∪(6,∞)
Given,
∣∣x−2∣−3∣>1
⟹∣x−2∣−3>1 or ∣x−2∣−3<−1
⟹∣x−2∣>4 or ∣x−2∣<2
⟹x−2>4 or x−2<−4 or −2<x−2<2
⟹x>6 or x<−2 or 0<x<4
So the answer is(6,∞)∪(−∞,−2)∪(0,4)
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