Question

if(x)=√x(x>0) and g(x)=x^2-1 are two real functions.find fog,and gof. is fog=gof?​

Answer 1

Heya!!

F(x) = √x And g(x) = x² - 1

Fog(x) = F{g(x)}

Fog(x) = F{x² - 1}

Fog(x) = √{x² - 1} .......... i

gof(x) = g{f(x)}

gof(x) = g{√x}

gof(x) = {(√x)² - 1 }

gof(x) = {x² - 1} .......... ii

From i and ii it's clear that

Fog ≠ gof

Answer 2

Step-by-step explanation:

✨Refer to the attachment...