Math, asked by maulikapatel0908, 9 months ago

If x*x+x*y+y*y=21 and x+√x*y+y=7 then find value of x-y

Answers

Answered by saijanani39644
1

Answer:

It's always a good idea to check the solution back in the original equations just ... how the equation then becomes x=-1-y when you are dividing by a positive 5 :(.

Step-by-step explanation:

Answered by tejeshkrishna80
0

Answer:

substitute EQ.1&2

Step-by-step explanation:

x^2+y^2+xy=21

x^2+y^2+2xy=(x+y)^2

(x+y)^2=21×2=42

x+y=root 42---EQ.1

x+root(xy)+y=7

root42+rootxy=7----EQ.2

substitute EQ1&2

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