if x×x+y×y=7xy show that 2log(x×y)=log x+log y+2 log3
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x² + y² = 7xy (given)
Add 2xy in both sides of above equation.
→ x² + y² + 2xy = 7xy + 2xy = 9xy
So (x + y)² = 9xy (Consider logarithm on both sides)
We get log (x + y)² = log 9xy
→ 2log (x + y)= log 9 + log x + log y
= log x + log y + log 3²
= log x + log y + 2 log 3
2 log (x + y) = log x + log y + 2 log 3
Hence proved.
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