Question

If x+x+y+y+y+y=35
y+y+y+y+y+y+y+x+x=41 So what would be the value of x and y?

Answer 1

Answer:

$x = \dfrac{27}{2}$ and y = 2.

Step-by-step explanation:

The given equations are-

x+x+y+y+y+y = 35

Or, 2x + 4y = 35        ------------- 1

y+y+y+y+y+y+y+x+x = 41

Or, 2x + 7y = 41         ------------- 2

Subtracting equation 2 from equation 1

We have-

(2x + 7y) - (2x + 4y) = 41 - 35

2x + 7y - 2x + 4y = 6

3y = 6

y = 2

put y = 2 in equation 2

We have-

2x + 7y = 41

2x + 7(2) = 41

2x + 14 = 41

2x = 41 - 14

2x = 27

$x = \dfrac{27}{2}$

Answer 2

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VALUE OF THE Y IS 2/7