Question

If x(x+y+z)=9, y(x+y+z)=16 and z(x+y+z)=144 then value of x is

Answer 1

x(x+y+z) = 9…………………………(1)
y(x+y+z) =16………………………...(2)
z(x+y+z) = 144………………………(3)
By adding these 3 equations
(x+y+z)^2 = 169
x+y+z = 13 .....................………(4)
from (1):
x(x+y+z) = 9
x(13) = 9.……{from (4)}
x = 9/13

Answer 2

Answer:

$\frac{9}{13}$

Step-by-step explanation:

x (x + y +z ) ---------------------------------------- Eq( 1 )              Eq = Equation

y (x + y + z ) --------------------------------------- Eq( 2 )

z ( x + y + z ) --------------------------------------- Eq( 3 )

On adding Eq(1) + Eq(2) + Eq(3)

x ( x + y + z ) + y ( x + y + z ) + z ( x + y + z)                

$( x + y + z )^{2}$ = 169

13² = 169

x + y + z = 13

x ( 13 ) = 9

x = $\frac{9}{13}$