Question

If x/y =[-1/3]-³ ÷[2/3]-⁴ , find the value of:


(a) [x/y]-¹ (b) [x/y + y/x)-¹​

Answer 1

Answer:

x/y =[-1/3]-³ ÷[2/3]-⁴

= -27/(81÷16)

x/y = -16/3

(a) [x/y]-¹ = -3/16

b) [x/y + y/x)-¹ = (-16/3 - 3/16)^(-1)

= ((-256-9)/48)^(-1)

= (-265/48)^(-1)

= -48/265