Question

if x/y=(-1/3)^-3÷(2/3)^-4,find the value of (x/y)^-1​

Answer 1

Given,

x/y = ((-1)/3)-3 ÷(2/3)-4

=(-1/3)-3 ÷2/3-4

=(-1/3)-9/2-4

= -1/3-9/2-4

=x/y= -53/6

Then,

(x/y)(-3x)/16y

= -53/6(-3/16× -53/6)

= -53/6×53/6×3/16.

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