if x/y=(-1/3)^-3÷(2/3)^-4 find the value of (x/y+y/x)^-1 please don't write any irrelevant answer here
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Answer:
28 4/9
Step-by-step explanation:
(x/y+y/x)^-1
= ((-1/3)^-3/(2/3)^-4) / ((2/3)^-4 / (-1/3)^-3)^1
-27/(5 1/16) / (5 1/16)/-27
-5 1/3/ -3/16
28 4/9
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