Math, asked by syedmd, 11 months ago

if x/y =(-1/3)^-3÷(2/3)^-4 find(x/y)^-1​

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Answered by Anonymous
7

Answer:plz mark my answer as brainlist

 \frac{x}{y}  =  \frac{ (\frac{ - 1}{3}) ^{ - 3} }{ (\frac{2}{3})^{ - 4}  }  \\  \\  \frac{x}{y}  =  \frac{ (\frac{3}{ - 1} ) ^{3} }{ (\frac{3}{2} ) ^{4} }  \\  \\  \frac{x}{y}  =  \frac{ \frac{27 }{ - 1} }{ \frac{81}{16} }  \\  \\  \frac{x}{y }  =  \frac{27}{ - 1}  \times  \frac{16}{81}  \\  \\  \frac{x}{y}  =  \frac{ - 16}{3}  \\  \\  (\frac{x}{y} )^{ - 1}  =  \frac{ - 16}{3}  \\  \\  \frac{y}{x}  =  \frac{3}{ - 16}

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