Math, asked by armitanayak12, 7 months ago

if x:y=1:3 then the ratio (7x^2+3xy) :(2xy+y^2) is​

Answers

Answered by ManickamSantosh
0

Answer:

16:5

Step-by-step explanation:

let x = 1k and y = 3k, so

\begin{aligned}

= \frac{7(k)+3(3k)}{2(k)+1(3k)} \\

= \frac{16k}{5k} \\

= 16:5

\end{aligned}

Answered by dreamrob
1

Given,

x:y=1:3

To Find,

(7x^2+3xy) :(2xy+y^2)

Solution,

x:y = 1:3 is given to us.

Let a variable a such that x:y= 1a: 3a

and x = a , y = 3a

Now we will put values of x and y in equation,

(7x^2+3xy) :(2xy+y^2)

(7(a)^2+3(a)(3a)) :(2(a)(3a)+(3a)^2)

(7(a)^2+9(a)^2) :(6(a)^2+9(a)^2)

(16(a)^2) :(15a^2) [a^2 are common so cancel them]

16:15

Hence, ration of (7x^2+3xy) :(2xy+y^2) is 16:15

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