Question

If (x+y)-¹ . (x-¹+y-¹) = x^p.y^q , then the value of p+q+3=​

Answer 1

Q:- ( x + y )^-1 × [ ( x )^-1 + ( y )^-1 ] =x^p × y^q

=》 1 ÷ ( x + y ) [ ( 1 ÷ x ) + ( 1 ÷ y ) ] =x^p × y^q

=》1 ÷ ( x + y ) [ ( x + y ) ÷ x y ] = x^p × y^q

=》1 ÷ x × y = x^p × y^q

=》( x × y )^-1 = x^p × y^q

=》 x^-1 × y^-1 = x^p × y^q

♤ On comparison

=》 p = -1 ; q = -1

♡ We have to prove { p + q + 2 = 0}

♤ Putting valu of p and q

=》 - 1 - 1 + 2

=》- 2 + 2

=》0

■ HENCE PROVED

HOPE HELPED

JAI HIND !!!

:-)

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