Math, asked by nokedureti, 17 days ago

If x+y=10 and x-y=6 .what is the value of x3_y3

Answers

Answered by Aashusindh
0

Answer:

520. (if you meant x^3 - y^3)

x = 6 - y and x = 10 + y. Since x = x, then 6 - y = 10 + y. Simplify to get y = -2. If y = -2 then x = 6 + 2 = 8. So x^3 - y^3 would be 8^3 - (-2)^3.

(2^3)^3 - (-1)^3 * 2^3 =

2^9 + 2^3 =

520.

Answered by mayursagare873
0

Answer:

Step-by-step explanation:

x+y=10- (x-y=6) =2y=16 y=8,x=2

x^3-y^3=(x-y)^3-3xy(x-y)

=6^3-3×16(6)

=216-48×6

=216-288

= -72

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