Question

If (x+y) = 10 and xy = 10, find the value of (x2 + y2

).​

Answer 1

Answer:

Property used =

(x+y)² = x² + 2xy + y²

Now putting the value

(10)² = x² + 2 (10) + y²

100 = x² + 20 + y²

100 - 20 = x² + y²

80 = x² + y²

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Answer 2

Answer:

$given \: that \: \: \: (x + y) = 10 \\( xy = 10) \\ \\ to \: find \: (x2 + y2) = what \\ \\ we \: know \: that \: (a + b)2 = (a2 + b2 + 2ab) \\ \\ now \: \\ (x + y)2 = (x2 + y2 + 2xy) \\ (10)2 = (x2 + y2 + 2 \times 10) \\ 100 = (x2 + y2) + 20 \\ (x2 + y2) = (100 - 20) \\ (x2 + y2) = 80$

hence value of (x2+y2)=80