Question

if x+y= 10 and xy = 21 find 2(x^2+y^2)

Answer 1

Answer:

X^2+y^2 = (x+y)^2 - 2xy = 10^2 - 2×21 = 58

Therefore, 2(x^2+y^2) = 2×58 = 116

Answer 2

Answer:

116 is your answer.

Step-by-step explanation:

2(x^2+y^2)

(x+y)^2=100

x^2+y^2+2xy=100

x^2+y^2+2(21)=100

x^2+y^2=58

2(x^2+y^2)=116

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