Question

if (x+y)=10 and xy=21 find 2(x²+y²)​

Answer 1

Answer:

116

Step-by-step explanation:

(x+y)=10

(x+y)^2=10^2

x^2 + y^2 + 2 * x* y=100

x^2 + y^2 +2*21=100

x^2 + y^2 =100-42

x^2 + y^2 =-58

2(x^2 + y^2 )=116