Question

if x+y=10 and xy=21 find xcube+ycube

Answer 1

Answer:

x3+y3=370

Step-by-step explanation:

x3+y3=(x+y)^3-3xy(x+y)

=(10)^3-3×21×10

=1000-630

=370....

√\________Anushka❤❤

Answer 2

Given:-

•x+y=10

•xy=21

To find:-

•Value of x³+y³

Solution:-

By,squaring both the sides in the equation,x+y=10,we get------

=>(x+y)²=(10)²

=>x²+y²+2xy=100

=>x²+y²+2×21=100

=>x²+y²=100-42

=>x²+y²=58

Now,x³+y³=(x+y)(x²+y²-xy)

=>(10)(58-21)

=>10×37

=>370

Thus,value of x³+y³ is 370.