if x+y=10,x^3+y^3 =30 then x^2-xy+y^2=
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Answer:
Given that, x+y=12 and xy=27
We know,
(x+y) 3 =x 3 +y 3 +3xy(x+y)
Therefore,
12 3 =x 3 +y 3 +3×27×12
1728=x 3 +y 3 +972
x 3 +y 3 =1728−972=756
∴x 3 +y 3 =756
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