Question

If x+y = 10 , y+z = 15 , x+z= 17 , then what is average of x, y, and z ?

Answer 1

average of x, y, z=

=(x+y)+(y+z)+(x+z)/6

=10+15+17/6

=7

Answer 2

x+y=10. y=10-x. eq1

y+z=15. y=15-z. eq2

x+z=17. x=17-z. eq3

eq.1. x+y=10

from eq.2. x+15-z=10

from eq.3. 17-z+15-z=10

=>32-2z=10

2z=22

z=11

substitute in eq 3... we get. x=6

substitute any one in eq.1 or eq.2 we get

y=4

Therefore,x=6,y=4,z=11

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