if x+y = 11 and xy = 17 find the value of x³+y³
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Answer:
x³+ y³ = 1870
Step-by-step explanation:
Using Identity (x+y)³ = x³+ y³ + 3xy(x + y)
⇒ x³+ y³ = (x+y)³ - 3xy(x + y)
Substituting the given values, x+y = 11 and xy = 17
x³+ y³ = 11³ - 3x17x11
= 11 x (121 - 51)
= 11 x 70
= 1870
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