Question

if x+y=11 and xy=28 then find x to the 2 + y to the power 2​

Answer 1

Step-by-step explanation:

Given:-

x+y = 11

xy = 28

To find:-

The value of x^2+y^2

Solution:-

Given that

x+y = 11--------(1)

xy = 28

On squaring (1) both sides then

=>(x+y)^2 = 11^2

We know that

(a+b)^2 = a^2+2ab+b^2

=>x^2+2xy+y^2=121

=>x^2+y^2+2xy = 121

=>x^2+y^2+2(28)=121

=>x^2+y^2+56 = 121

=>x^2+y^2 = 121-56

=>x^2+y^2 = 65

Therefore,x^2+y^2 = 65

Answer:-

The value of x^2+y^2 for the given problem is 65

Used formula:-

• (a+b)^2 = a^2+2ab+b^2