Math, asked by 004024, 1 month ago

If (x+y)=11 and xy =3 find x²+y² *​

Answers

Answered by AnswerFactory
0

Answer:

16 & 49

Step-by-step explanation:

You would start by making one of the equations into an x= or y= … i will make x-y=3 into x=y+3. you plug that into the other equation in place of it's x. so x+y=11 will be (y+3)+y=11. it will be simplified to 2y+3=11. then you subtract 3 from each side of the equal sign to make 2y=8. to get rid of the 2 in front of the y you divide each side by 2 to find what y equals, which is y=4 . now you found y. plug that 4 for y in any equation to find x. you will have your answer

  • x+y=11
  • x+4=11
  • x=11-4
  • x=7

So,

x²+y² = 7²+4²

= 49+16

= 65

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Answered by Aaradhanatripathi
2

using the identity (x+y)²=x²+y²+2xy

(11)²=x²+y²+2(3)

121=x²+y²+6

121-6=x²+y²

115=x²+y² - ans

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