If x+y=12 & xy=14, find the value of(x^2+y^2)
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x + y = 12
so, (x+y)^2 = (12)^2
x² + y² +2xy = 144
x² + y² + 2*14 = 144
x²+ y² = 144 -28 = 116
so, (x+y)^2 = (12)^2
x² + y² +2xy = 144
x² + y² + 2*14 = 144
x²+ y² = 144 -28 = 116
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