Question

If X + Y = 12 and X Y=14 find the value of (x² + Y²)

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Answer 1

Answer:

Given:- x+y=12

xy= 14

Solution:-

${x}^{2} + {y}^{2} \\ = {(x + y)}^{2} - 2xy \\ = {12}^{2} - 2 \times 14 \\ = 144 - 28 \\ = 116$

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Answer 2

Answer:

116

Step-by-step explanation:

• Given data

=>x + y = 12 ---(1

=>xy = 14-----(2

• On squiering both side of equation ----(1 we get

=>(x+ y)^2 = 12^2

=>x^2 + y^2 + 2xy = 144

• on putting the value of xy from equation ----(2

=>x^2 + y^2 + 28 = 144

=>x^2 + y^2 = 116

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