Question

if x+y=12 and xy=14, find the value of
${x}^{2} + {y}^{2}$
​

Answer 1

$\huge\boxed{\underline{\underline{\green{\tt Solution}}}} </p><p></p><p>$

${x}^{2} + {y}^{2}$

$= {(x + y)}^{2} - 2xy$

$= {12}^{2} - 2 \times 14$

$= 144 - 28$

$= 116$

$</p><p></p><p>\displaystyle\textcolor{red}{Please \: Mark \: it \: Brainliest}$

Answer 2

Given x+y=12 ---(1)

xy = 14 ------(2)

On Squaring both sides of equation (1) ,we get

(x+y)²= 12²

=> x²+2xy+y² = 144

_________________________

By algebraic identity:

$(a + b) {}^{2} = a {}^{2} + 2ab + b {}^{2}$

________________________________

=> x²+y² +2×14=144

• From (2)•

=> x²+y²+28 = 144

=> x²+y² = 144-28

=> x²+y² = 116

Therefore

x²+y² = 116

Hope u get it....!!