Question

If x+y=12 and xy=14 find the value of (x^2+y^2)​

Answer 1

Answer:

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Answer 2

$x + y = 12$

$xy = 14$

$x {}^{2} + y {}^{2} = {?}$

We know,

$(x+ y) {}^{2} = x {}^{2} + y {}^{2} + 2xy$

Substitute x+y=12 and xy=14,we get

$(12) {}^{2} + x {}^{2} + y {}^{2} + 2(14)$

$144 = x {}^{2} + y {}^{2} + 28$

$144 - 28 = x {}^{2} + y {}^{2}$

$116 = x {}^{2} + y {}^{2}$

Thus ,the value of x²+y² is 116