If x+y =12 and xy =14,find the value of (x²+y²)
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x+y=12
squaring on both th sides
(x+y)^2= (12)^2
x^2+y^2+2xy=144
x^2+y^2+2(14)=144
x^2+y^2=144-28
x^2+y^2=116
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