Question

if x+y=12 and xy=14 find the value of x²+y²​

Answer 1

Answer:

hi

Step-by-step explanation:

x+y=12

(x+y)²=12² ( squaring both side )

x²+y²+2xy=144

x²+y²+2(14)=144 (xy=14)

x²+y²=144-28

x²+y²=116

Answer 2

Answer:

$x + y = 12 \\ (x + y {)}^{2} = 1 {2}^{2} \\ {x}^{2} + 2xy + {y}^{2} = 144 \\ {x}^{2} + {y}^{2} + 2(14) = 144 \\ {x}^{2} + {y}^{2} + 28 = 144 \\ {x}^{2} + {y}^{2} = 144 - 28 \\ {x}^{2} + {y}^{2} =116$