Math, asked by ashpreetkaur7432, 4 months ago

if x+y =12 and xy = 14 find the value of (x²+y²)​

Answers

Answered by muskanperween225
1

Step-by-step explanation:

 {x}^{2}  +  {y}^{2}

 =  {(x + y)}^{2}  -2 xy

 =  {(12)}^{2}  - 2 \times 14

 = 144 - 28

 = 116

Answered by visheshs519
0

Answer:

116

Step-by-step explanation:

x²+y²=x²+y²+2xy

(X+y)²=x²+y²+2(14)

(12)²=x²+y²+28

144-28=x²+y²

x²+y²=116

hope it helps..........

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