Question

If x+y=12 and xy=14, find the value of (x2+y2)​

Answer 1

Answer:

x²+y²=116

Step-by-step explanation:

(x+y)²= x²+y²+2xy

(12)²=x²+y²+2(14)

144= x²+y²+28

x²+y²= 144-28

x²+y²= 116

Answer 2

Hello Friend,

I hope You understand this

Given,

x+y=12 and xy=14

x+y=12

Squaring both sides, we get,

$(x+y)^{2} = 12^{2}$

$x^{2}+ y^{2} +2xy=144$

$x^{2}+ y^{2} +2(14)=144$  (since xy=14)

$x^{2}+ y^{2} =144-28$

$x^{2}+ y^{2} =116$