Question

If x+y=12 and xy=14, Find the value of (Xpower 2 +ypower 2)​

Answer 1

Answer:

x+y=12

(x+y)²=12² ( squaring both side )

x²+y²+2xy=144

x²+y²+2(14)=144 (xy=14)

x²+y²=144-28

x²+y²=116

Step-by-step explanation: mark as brainlist

Answer 2

Answer:

${x}^{2} + {y}^{2} = 116$

${(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ putting \: the \: given \: values \: in \: identity \\ {(12)}^{2} = {x}^{2} + {y}^{2} + 2 \times (14) \\ 144 = {x}^{2} + {y}^{2} + 28 \\ 144 - 28 = {x}^{2} + {y}^{2} \\ 116 = {x}^{2} + {y}^{2}$