Question

If x+y=12 and xy=14,find the values of (x^2+y^2)

Answer 1

Answer:

Step-by-step explanation:

(x+y)^2 = x^2 + 2xy + y^2

12^2 = x^2 + y^2 + 2(14)

144= x^2+y^2+28

144-28=x^2+y^2

x^2+y^2=116