Question

If x+y=12 and xy=14 find x^2+y^2[Hint: x^2+y^2=(x+y)^2-2xy]

Answer 1

Step-by-step explanation:

using (a+b)^2

we get,

x^2+y^2+2xy=12^2=144

{replacing value of xy}

x^2+y^2+28=144

x^2+y^2=116

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