If x + y = 12 and xy = 14, then find the value of x² + y².
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Given, x + y = 12 and xy = 14 x + y = 12 Squaring both sides, we get, (x + y)^2 = 12^2 = >x^2 + y^2 + 2xy = 144 = >x^2 + y^2 + 2(14) = 144 = >x^2 + y^2 ..
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116
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see the attached image i have solved in that
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