Question

if x+y = 12 and xy = 14 then the value of [x2+y2] is

Answer 1

Answer:

${x}^{2} + {y}^{2} = 116$

Step-by-step explanation:

$x + y = 12 \\ {(x + y)}^{2} = 144 \\ {x}^{2} + {y}^{2} + 2xy = 144 \\ \\ {x}^{2} + {y}^{2} = 144 - 2xy \\ {x}^{2} + {y}^{2} = 144 - 2(14) \\ \\ {x}^{2} + {y}^{2} = 144 - 28 = 116 \\ \\ {x}^{2} + {y}^{2} = 116$