if x-y=12 and xy=25/4,findx+y
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answer=2√42
Step-by-step explanation:
x-y=12
(x-y)^2=144
x^2+y^2-2xy=144
x^2+y^2-2(25/4)=144
x^2+y^2-25/2=144
x^2+y^2=144+25/2
x^2+y^2=(288+25)/2
x^2+y^2=313/2.....(1)
(x+y)^2=x^2+y^2+2xy
(x+y)^2=(313/2)+2(25/4)
(x+y)^2=(313/2)+(25/2)
(x+y)^2=(313+25)/2
(x+y)^2=336/2
(x+y)^2=168
x+y=√168
x+y=√4 * √42
x+y=2√42
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