Question

if x+y=12 and xy=27, find the value of x^2+y^2​

Answer 1

Step-by-step explanation:

x+y=12

x=12-y

xy=27

(12-y)y=27

12y-y²=27

y²-12y+27=0

y²-3y-9y+27=0

y(y-3)-9(y-3)=0

(y-9)(y-3)=0

y=9,y=3

Let y=3

xy=27

3x=27

x=9

Let y=9

9x=27

x=3

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