Math, asked by muhammadrafiu1907, 9 months ago

If x+y=12 and xy=27,find the value of x^2+y^2

Answers

Answered by sayalimahajan39
0

Answer

x=9or3 y=3or9

Step-by-step explanation:

x+y=12

x=27/y

27/y+y=12

27+y^2/y=12

27+y^2=12y

we get a quadratic equation

y^2-12y+27=0

y^2-9y-3y+27=0

y(y-9)-3(y-9)=0

(y-3)(y-9)=0

y=3 or y=9

x×3=27

x=9

x×9=27

x=3

Answered by Jayasripeddi
0

Step-by-step explanation:

Given x+y=12 and xy=27

Now, squaring on both sides,we get

  • (x+y)^2=12^2

we know that (a+b)^2=a^2+2ab+b^2

  • x^2+2xy+y^2=144

but we have xy=27

  • x^2+y^2+2(27)=144
  • x^2+y^2+54=144
  • x^2+y^2=144-54
  • x^2+y^2=90
  • The value of x^2+y^2=90
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