if x+y=12 and xy=27. Find the value of x (cube) and y (cube)
Answers
Answered by
7
( x+y) ³ = x³+ y³+3xy (x+y)
(12)³ =x³+y³+3 ×27(12)
1728 = x³+y³ 972
1728-972 =x³+y³
756
(12)³ =x³+y³+3 ×27(12)
1728 = x³+y³ 972
1728-972 =x³+y³
756
Similar questions