if X + Y = 12 and xy = 27 find the value of x cube + y cube
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Given (x + y) = 12 and
xy = 27
Recall, x3 + y3 = (x + y)3 – 3xy(x + y) ⇒ x3 + y3 = (12)3 – 3(27)(12)= 1728 – 972 ∴ x3 + y3 = 756
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Answered by
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Answer:
x3+y3=756
Step-by-step explanation:
Hey mate
Given :- x+y=12. -----(1)
xy=27. -------(2)
To Find :- x3+y3
Solution x3+y3=(x+y)(x2+y2-xy). --(3)
First of all we have to find the value of x2+y2
so
(x+y)=12
square at both side
(x+y)2=(12)2
x2+y2+2xy=144
x2+y2 +2*27 = 144
x2+y2 + 54=144
x2+y2=90. ------(4)
Now put 1&2&4 in 3
x3+y3 = (12)(90-27)
x3+y3 = 12*63
x3+y3=756
Hope this will help u
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