Math, asked by karan22556, 5 months ago

if x+y=12 and xy=27, find the value of x³+y³​

Answers

Answered by satishgoyal409
2

756

Step-by-step explanation:

x+y=12

Cube both sides

(x+y)³=12³

x³+y³+3xy(x+y)=1728

x³+y³+3×27×12=1728

x³+y³+972=1728

x³+y³=756

Answered by megha32190
0

Answer:

x+y=12....... 1]

x+y=27........ 2]

eq.. 1] write as.. x+y=12

y=12-x......... 3]

substitute the eq 2]>x+y=27

x+(12-x)=27

x+12-x=27

2x+12=27

2x=27-12

2x=15

x=15/2

x=7.5.........

substitute the eq 3]>y=12-x

y=12-7.5

y=4.5.......

verification:::: By eq... 1]x+y=12

. 7.5+4.5=12

=12.0=12....

Xcube+ycube

(7.5) cube+(4.5) cube

421.875+91.125

=513.000.............

If u r satisfied means....

I'm really glad.............................

Similar questions