Math, asked by khanghura1, 3 months ago

if x+y = 12 and xy=27 find the value of xsquare and y square​

Answers

Answered by shashirajgupta7
0

Step-by-step explanation:

x^2 = 9 or 81

y^2 = 9 or 81

this is the right answer

Answered by Anonymous
1

Answer:

Hola!

Here's how to do it:-

Since x + y = 12

Let's take y as x-12 so that it will be easier to calculate.

Its given that xy=27.

Substituting our new values to this equation, we get:

(x) (x-12) = 27

x^{2}- 12x = 27

Here, we can use the completing the square method.

x^{2} - 12x+ (\frac{12}{2})^{2}   = 27+ (\frac{12}{2})^{2}

x^{2} - 12x+ 6^{2}  = 27 -6^{2}

x^{2} - 12x+ 6^{2}  = 27-36

x^{2} - 12x+ 6^{2}  = 9

(x+6)^{2}  = 9

x-6 = \sqrt{9}

x - 6 = 3

x = 3+6  

x = 9

So, since y was x-12,

y would be

9-12

value of y is 3.

Value of x is 9 and value of y is 3.

Values of x^{2} and y^{2}

x^{2}= 9^{2}

9^{2} = 81

Value of y^{2}

y^{2} = 3^{2}

3^{2} = 9

Final answer would be:-

Value of x^{2} is 81 and Value of y^{2} is 9

Hope it helps!

Keep learning!

:-)

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