If x+y =12 and xy =27 then find tge value of x^3+y^3
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xy=27
x=27/y
now substituting the value of x to the above equation
ie. x+y=12
27/y+y=12
27+y²/y=12
27+y²=12y
y²-12y+27=0
sum= -12
product=27
y²-3y-9y+27=0
y(y-3)-9(y-3)=0
(y-9)(y-3)=0
y=9
y=3
substituting the value o y in the first equation
x=27/3 or x=27/9
x=9 or x=3
x³+y³
when x=3 and y=9
3³+9³=27+729
=756
when x=9 and y= 3
9³+3³=729+27
=756
∴x³+y³=756
hope it helps
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