if x + y = 12 and xy = 27 then find the value of x3 + y3.
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34
(x+y)³=x³+y³+3xy(x+y)
12³ =x³+y³+3×27×12
1728 =x³+y³+972
x³+y³ =1728-972
=756
12³ =x³+y³+3×27×12
1728 =x³+y³+972
x³+y³ =1728-972
=756
Answered by
4
Answer:
756
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