if x+y=12 and xy=27 then what is (x+y)^2 and x^2+y^2
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Answer:
( x + y )² = 144
x² + y² = 142
Step-by-step explanation:
Given,
x + y = 12
xy = 1
To find : -
1. ( x + y )²
2. x² + y²
1.
( x + y )²
= 12²
= 144
2.
( x + y )²
Formula / Identify : -
( a + b )² = a² + b² + 2ab
Here,
a = x
b = y
( x + y )² = x² + y² + 2ab
x² + y² = ( x + y )² - 2ab
= 144 - 2 ( 1 )
= 144 - 2
x² + y² = 142
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