Question

. If x + y = 12 and xy = 3, find the value of
(x2+ y2).​

Answer 1

Answer:

bruh

Step-by-step explanation:

Answer 2

Answer:

${\large{\sf{\underline{Given}}}}$

$\: \: \: \: \: \: \: \: { \sf{❍ \:x + y = 12 }}$

$\: \: \: \: \: \: \: \: { \sf{❍ \:xy = 3 }}$

${\large{\sf{\underline{To \: Find}}}}$

$\: \: \: \: \: \: \: \: { \sf{❍ \: Find \: Value \: of \: {x}^{2} + {y}^{2} ???}}$

${\large{\sf{\underline{Solution}}}}$

• Let us do squaring on both sides for x + y = 12 .Thus we can get the answer. let's start solution

Doing SOBS:-

${\underline{ \sf{★ \: By\: Solving,}}}$

${\dashrightarrow{\sf{ {(x + y)}^{2} = {12}^{2} }}} \\ \\ \\ {\dashrightarrow{\sf{ {x}^{2} + {y}^{2} + 2xy = 144}}} \\ \\ \\ {\sf{From \: Question \: Value \: of \: xy \: =3}} \\ \\ \\ {\dashrightarrow{\sf{ {x}^{2} + {y}^{2} + 2(3) = 144 }}} \\ \\ \\ {\dashrightarrow{\sf{ {x}^{2} + {y}^{2} + 6 = 144 }}} \\ \\ \\ {\dashrightarrow{\sf{ {x}^{2} + {y}^{2} = 144 - 6 }}} \\ \\ \\ {\dashrightarrow{\sf{ {x}^{2} + {y}^{2} = 138 }}} \\ \\ \\ \: { \boxed{ \boxed{ \therefore{ \sf{ \pink{Value \: of \: {x}^{2} + {y}^{2} = 138 }}}}}}$